Q:- An ideal gas expand in an adiabatic turbine from 1200K and 900kpa to 1000K . Determine the turbine inlet volume flow rate of the gas in m^3/s required to produce turbine work output at the rate of 650 KW. The average values of the specific heats for this gas over the interested temprature range are Cp=1.13 KJ/Kg.K and Cv=0.83 Kj/Kg.k . The gas constant R= 030 KJ/Kg.k. Please assume constant specific heats.
Answer :-
Given ,
Inlet pressure, P1 = 900Kpa
inlet temprature, T1 = 1200K
Exit temprature ,T2 = 1000K
Work output , W = 650KW
Now , We know that
Work output , W = mCp(T1 - T2)
650 = mx1.13x(1200 - 1000)
m = 2.8761 Kg/sec
Also, By using ideal gas equation
PV = m RT
900000xV = 2.8761x030x1000x1200
V = 1.15044 m^3/Kg
S, Volume flow rate , Q = Vxm
Q = 1.15044 x 2.8761
Q = 3.3087 m^3/sec
Hence , the volume flow rate of gas through the turbine is 3.3087 m^3/sec
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