Q:-
The system shown is in equilibrium . determine the forces Fab (T1) and Fbc (T2), the object has a weight of 3540lb.
ANSWER :-
From the figure:-
Tanθ = 3/4
so, θ = 36.86 degree
Forces in X- direction
T1cos36.86 = T2cos45
T1= 0.8897T2.....................................................(1)
Also, Forces in Y-direction
T1sin36.86 + T2sin45 = 340 lb
(0.8897T2)(0.599) + T2(0.7071) = 340 lb .........................[from Eq (1)]
So, T2 = 274.186 lb
Fbc = 274.186 lb ......................Answer
Also , T1 = (0.8897)(274.186)
T1 = 243.94 lb
So, Fab = 243.94 lb ....................Answer
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