The shunt field resistance of 110 ohms of a DC shunt generator is having 4 pole and an armature resistance of 1.5 ohms has 250 lap connected conductors in the armature winding. If load resistance of 21 ohms is connected across the armature terminals and the generator is driven at 1015 rpm and the flux per pole of the machine is 0.03 Wb. current and power absorbed ???

 The shunt field resistance of 110 ohms of a DC shunt generator is having 4 pole and an armature resistance of 1.5 ohms has 250 lap connected conductors in the armature winding. If load resistance of 21 ohms is connected across the armature terminals and the generator is driven at 1015 rpm and the flux per pole of the machine is 0.03 Wb. current and power absorbed ???

ANSWER - 

Generated EMF , E = φ. Z. N .p/(60XA)

                            = (0.03x250x1015x4)/(2x60) = 253.75 volt

by natural mode analysis,

v - 253.75 + v/110 +v/21 =0

so, v =240.13  volt

Now, Amature current , I = (E- V)/R  = (253.75 - 240.13)/1.5 = 9.08 A

So, power , P = (240.13)^2 / 21 = 2745.82  watt